MATH SOLVE

3 months ago

Q:
# A rectangular lawn measures 80 ft by 120 ft. Part of the lawn is torn up to install a sidewalk of uniform width around it. The area of the new lawn is 3200 ft2. How wide is the sidewalk? The sidewalk is nothing ▼ ft squared ft cubed ft wide.

Accepted Solution

A:

Answer:Both answers will give an area of 2400 ft2
but with x=60 we have lawn dimensions -60 ft by -40 ft so this is out
x = 10 ft width for the sidewalk
Check: New lawn dimensions
(80-2x)(60-2x) = 60(40) = 2400 ft^2 Step-by-step explanation:Draw a diagram:
We have a rectangle inside a rectangle.
The larger outside rectangle is the original lawn: 80ft by 60 ft with area 4800 ft2
The smaller inside rectangle is (80-2x)by(60-2x) where x is width of the new sidewalk.
Area of new lawn is 2400 ft^2 (80-2x)(60-2x) = 2400
4800 - 160x - 120x + 4x2 = 2400
4x2 - 280x + 2400 = 0
Factor out a 4
x2 - 70x + 600 = 0
(x-60)(x-10) = 0
x = 60 ft or x = 10 ft